Paderborn to claim first win of the league season against Osnabruck
Paderborn vs VfL Osnabruck - 04/08/2023
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On Friday evening, Paderborn hosts Osnabruck at the Home Deluxe Arena in the 2. Bundesliga, as both teams look for their opening win of the league season.
Paderborn
After a highly promising pre-season campaign in which they recorded four straight wins, including against Bundesliga outfit Bayer Leverkusen, Paderborn lost their opening 2. Bundesliga game 5-0 at Greuther Furth.
The defeat just continues a poor run of league form from last season, as Paderborn heads into this clash on the back of just one victory in their previous five games in the German second tier.
However, one major plus from the end of last season was Paderborn’s home form in the second tier of the German game, as they have won six of their previous eight league matches on home soil.
One of the main reasons for their stellar home form was a prolific attack, as Paderborn have scored at least two goals in four of their last five matches on home soil in the 2. Bundesliga.
Osnabruck
Like the hosts, the visitors kicked off their 2. Bundesliga campaign with a loss, going down 3-2 to Karlsruhe on home soil. The defeat was disappointing as Osnabruck had a promising pre-season campaign.
Osnabruck’s primary objective this season will be to maintain their 2. Bundesliga status after winning promotion.
They last featured in the German second tier in season 2020/21, as relegation brought an inevitable poor end-of-season record, as they have won just two of their previous nine games in the 2. Bundesliga, having suffered six defeats in the run.
The poor run also included winning just two of their last nine away matches in the German second tier.
What does Forebet predict?
Forebet predicts that Paderborn will pick up their first league win of the season in a high-scoring game to kickstart their 2. Bundesliga campaign.
Home team
Away team
Pred
Correct score
Avg. goals
Weather conditions
Coef.
Score
Live
coef.
De2
582220
1
2 - 1
3.16
20° 1.62
1.62
4.00
5.25
no
no
no
1 - 1(0 - 0)